What is the Wilkinson combiner efficiency when combining amplifiers with different output power levels?
Wilkinson Combiner Power Balance
Understanding the Wilkinson combiner's behavior with unequal inputs is important for: designing systems where PAs have different output powers, analyzing the impact of PA failure or gain variation, and optimizing the power distribution in adaptive transmitters.
Practical Implications
- PA gain variation: In production, PAs have ±1-2 dB gain variation. A 2 dB gain difference (P1 = 1.58×P2): combining efficiency = 99.6%. The impact is negligible
- Failed PA: If one PA fails completely (P2 = 0): efficiency = P1/(4×P1) = 25%. Only 25% of the remaining PA's power reaches the output; the other 75% is split between the failed port (reflected) and the isolation resistor. This is why high-isolation combiners are important for graceful degradation
η = (√P₁ + √P₂)² / (4×(P₁+P₂))
For P₁=P₂: η = (2√P)²/(8P) = 4P/8P×4 → 100%
For P₁=2P₂: η = (√2+1)²/(4×3) = 5.83/12 = 97.1%
Power to isolation resistor: P_iso = (√P₁ - √P₂)²/4
For P₁=10W, P₂=5W: P_iso = (3.16-2.24)²/4 = 0.21W
Frequently Asked Questions
Does phase imbalance also cause loss?
Yes. Phase imbalance between the two inputs also reduces the combining efficiency: P_out = P1 + P2 + 2×sqrt(P1×P2)×cos(delta_phi). For equal-power inputs with phase error: P_out = 2P × (1 + cos(delta_phi)) / 2 = P × (1 + cos(delta_phi)). Efficiency: eta = (1 + cos(delta_phi)) / 2. For delta_phi = 10 degrees: eta = 98.5%. For delta_phi = 30 degrees: eta = 93.3%. For delta_phi = 90 degrees: eta = 50%. Combined amplitude and phase imbalance: both effects add, further reducing the efficiency.
How do I handle large power imbalance?
If the PAs intentionally produce different power levels: use an unequal-split combiner (known as an asymmetric Wilkinson or a tapered line combiner). The unequal combiner has different impedance arms designed to match the different PA impedances and combine unequal powers with high efficiency. For example: a 2:1 power ratio combiner has: port 1 impedance = 50×sqrt(3) = 86.6 ohms, port 2 impedance = 50/sqrt(3) = 28.9 ohms, and achieves 100% combining efficiency for the designed power ratio.
What about N-way combining with unequal PAs?
In an N-way binary Wilkinson combiner (cascaded 2-way stages): each 2-way stage independently combines its two inputs. If all PAs produce equal power: uniform efficiency at each stage. If some PAs produce different power: the efficiency loss accumulates through the combining tree. For best efficiency: pair PAs with the closest output powers at the first combining level (so each 2-way combiner sees the smallest imbalance). This minimizes the power dissipated in the isolation resistors.