Filters and Frequency Selectivity Filter Types and Responses Informational

How do I calculate the unloaded Q required for a resonator to achieve a specific filter insertion loss?

The minimum unloaded Qu for a given filter insertion loss target is: Qu ≥ 4.343 × Σgi / (IL_target × FBW), where Σgi is the sum of the lowpass prototype element values, IL_target is the maximum acceptable insertion loss in dB, and FBW is the fractional bandwidth. Example: a 6-pole Chebyshev filter with 0.1 dB ripple (Σgi ≈ 7.2), 2% fractional bandwidth, and 1 dB maximum loss requires Qu ≥ 4.343 × 7.2 / (1 × 0.02) = 1,563. This rules out microstrip resonators (Qu ~200) and requires cavity or dielectric resonator technology.
Category: Filters and Frequency Selectivity
Updated: April 2026
Product Tie-In: Filters, Diplexers, Multiplexers

Q Requirement Calculation

The unloaded Q requirement is the most critical specification that determines the resonator technology for a given filter. If the available Qu is insufficient, no amount of design optimization can achieve the target insertion loss. This relationship is fundamental to filter physics and cannot be circumvented.

ParameterLC LumpedCavitySAW/BAW
Q Factor50-2001,000-20,000500-2,000
Frequency RangeDC-3 GHz0.1-40 GHz0.1-6 GHz
Insertion Loss1-6 dB0.2-2 dB1-4 dB
SizeSmall (PCB)Large (machined)Very small (chip)
TuningFixed or varactorMechanical screwFixed
Common Questions

Frequently Asked Questions

What if my available Q is marginal?

If the calculated Qu requirement is close to the available resonator Q, the filter will have higher loss than the target and a rounded passband shape (the sharp corners of the ideal response become rounded). Reducing the filter order or increasing the bandwidth are the only remedies, both of which sacrifice selectivity.

How do I measure resonator Q?

Measure the resonator as a one-port or two-port reflection using a VNA. Fit the resonance to extract the loaded Q (QL) and the coupling coefficient (β). Then Qu = QL × (1+β) for single-port or Qu = QL × (1+β1+β2) for two-port. Alternatively, measure the 3 dB bandwidth of the transmission peak through a very loosely coupled resonator.

Does temperature affect Q?

Yes. Metal cavity Q decreases at high temperature because resistivity increases (copper resistance increases ~0.4% per °C). Dielectric resonator Q decreases if the dielectric loss tangent increases with temperature. Superconducting resonators lose their Q above the critical temperature. Budget 10-20% Q reduction over the operating temperature range.

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