Cylinder Function
Why Cylindrical Geometry Demands Bessel Solutions
When the Helmholtz wave equation is separated in cylindrical coordinates (ρ, φ, z), the angular part yields harmonic functions ejnφ with integer order n, the axial part yields traveling waves e−jβz, and the radial part collapses to Bessel's equation. The radial solutions are the cylinder functions. This is the cylindrical analog of using sines and cosines in rectangular problems or Legendre functions in spherical problems. Because Bessel's equation is second order, it always has two linearly independent solutions: Jn(x), which is finite and oscillatory at the origin, and Yn(x), which diverges logarithmically (n = 0) or as a negative power (n ≥ 1) as the argument approaches zero.
The physics of the region picks which combination survives. Inside a solid air-filled circular guide the field must remain finite on the axis, so only Jn is admissible and Yn is discarded. In a coaxial structure the inner conductor removes the axis from the field region, so both Jn and Yn are retained and combined to satisfy the conditions at both conductor radii. For radiation and scattering, the Hankel functions Hn(1) = Jn + jYn and Hn(2) = Jn − jYn are preferred because they represent inward and outward traveling cylindrical waves, with Hn(2) satisfying the radiation condition for an outgoing wave.
For the engineer, the practical payoff is that all the eigenvalue tables, mode charts, and cutoff frequency formulas of cylindrical structures reduce to the tabulated roots of these functions. Modern field solvers still evaluate cylinder functions either directly through recurrence relations or through the asymptotic large-argument forms once the radial argument kr grows beyond about 10.
Governing Equation and Key Roots
x2y″ + xy′ + (x2 − n2)y = 0
General cylinder-function solution:
y(x) = A·Jn(x) + B·Yn(x) ≡ C·Hn(1)(x) + D·Hn(2)(x)
Hankel (traveling-wave) forms:
Hn(1)(x) = Jn(x) + jYn(x) Hn(2)(x) = Jn(x) − jYn(x)
Circular-waveguide cutoff:
TMnm: Jn(kca) = 0 → kc = pnm / a
TEnm: Jn′(kca) = 0 → kc = p′nm / a fc = c·kc / (2π)
Large-argument asymptote:
Jn(x) ≈ √(2 / πx) × cos(x − nπ/2 − π/4)
Example: a = 10 mm air-filled guide, TE11 with p′11 = 1.841 → fc ≈ 8.79 GHz; TM01 with p01 = 2.405 → fc ≈ 11.5 GHz.
The Three Cylinder Functions Compared
| Function | Symbol | Behavior at x → 0 | Behavior at x → ∞ | Typical Use |
|---|---|---|---|---|
| Bessel, first kind | Jn(x) | Finite (J0=1, Jn≥1=0) | Decaying oscillation ∝ 1/√x | Solid circular guide, on-axis fields |
| Neumann, second kind | Yn(x) | Diverges (−∞) | Decaying oscillation ∝ 1/√x | Coaxial / annular regions |
| Hankel, first kind | Hn(1)(x) | Diverges (via Yn) | Inward traveling wave e+jx/√x | Incoming cylindrical waves |
| Hankel, second kind | Hn(2)(x) | Diverges (via Yn) | Outgoing wave e−jx/√x | Radiation, scattering, antennas |
| Modified Bessel | In, Kn | In finite, Kn diverges | In grows, Kn decays | Evanescent / below-cutoff fields |
Frequently Asked Questions
When do you use Hankel functions instead of Bessel functions of the first kind?
Jn(x) is finite at the origin, so it is used inside a solid cylindrical region such as an air-filled circular guide. Yn(x) diverges as x approaches zero, so it is dropped on the axis but kept in annular regions like a coaxial line. The Hankel forms Hn(1) = Jn + jYn and Hn(2) = Jn − jYn represent inward and outward traveling cylindrical waves and are the natural basis for radiation and scattering, since Hn(2)(kr) satisfies the Sommerfeld radiation condition at large radius.
How do Bessel function roots set the cutoff frequency of a circular waveguide?
The wall at radius a selects discrete eigenvalues. TM modes need Jn(kca) = 0, so kca equals the root pnm; TE modes need Jn′(kca) = 0, so kca equals p′nm. Then fc = c × root / (2πa). The dominant TE11 uses p′11 = 1.841, giving about 8.79 GHz for a 10 mm radius guide; TM01 uses p01 = 2.405, giving about 11.5 GHz.
What is the asymptotic form of a cylinder function for large argument?
For large x every cylinder function decays algebraically as 1/√x, a slower falloff than the 1/r of a spherical wave. Jn(x) ≈ √(2/πx) × cos(x − nπ/2 − π/4), and Yn(x) uses the sine of the same phase. The 1/√x rolloff reflects energy spreading over a cylindrical wavefront whose circumference grows with radius, so power per unit length stays constant while amplitude falls as 1/√r. Solvers switch to these trigonometric forms once kr exceeds about 10, holding relative error under roughly 1 percent.