Waveguide Engineering

Cutoff Wavelength

/KUHT-awf WAYV-length/ (symbol λc)
The longest free-space wavelength that a particular waveguide mode will carry, fixed entirely by the cross-section geometry rather than the dielectric fill. A wave whose free-space wavelength exceeds λc (equivalently, a frequency below the cutoff frequency) cannot propagate; its propagation constant turns purely imaginary and the field collapses into an evanescent mode that decays exponentially down the guide. For the dominant TE10 mode of a rectangular guide the rule is simply λc = 2a, twice the broad-wall width, so a WR-90 guide (a = 22.86 mm) cuts off at 45.72 mm, or 6.557 GHz.
Category: Waveguide Engineering
Symbol: λc
TE10 rule: λc = 2a

How Geometry Sets the Cutoff

A hollow metallic waveguide behaves as a high-pass structure: it transmits energy only above a sharply defined threshold and rejects everything below it. That threshold is most naturally expressed as a wavelength because, for a given mode, it depends only on the guide's physical cross-section. The cutoff wavelength is the boundary case where the transverse field pattern exactly fits the guide walls with zero longitudinal phase progress, meaning the wave bounces purely sideways and makes no forward headway. Any free-space wavelength longer than λc over-fills the cross-section and can no longer satisfy the boundary conditions as a traveling wave.

Each mode (TE10, TE20, TM11, and so on) has its own cutoff wavelength. The mode with the longest λc, and therefore the lowest cutoff frequency, is the dominant mode; for standard rectangular guide that is TE10. The usable single-mode bandwidth of a guide is the span between the dominant-mode cutoff and the next higher-order cutoff (TE20 at λc = a, or half the dominant value). Engineers deliberately operate inside this window so that only one well-behaved field pattern carries the energy, avoiding the multimode dispersion and mode beating that would otherwise corrupt the signal.

Because λc is set by geometry and not by frequency or material, it is the most stable design anchor a waveguide engineer has. Filling the guide with a dielectric of relative permittivity εr leaves the cutoff wavelength unchanged but lowers the cutoff frequency by a factor of √εr, a trick used to shrink components without changing the metalwork.

Below Cutoff: The Evanescent Region

When a signal sits below cutoff, the guide does not simply reflect it at the mouth; the field penetrates a short distance and decays exponentially. The attenuation rate grows rapidly the further below cutoff the signal is, reaching about 27.3 dB per broad-wall width for a deeply sub-cutoff TE10 mode. This predictable, frequency-stable rolloff is exploited in waveguide-below-cutoff (WBCO) attenuators, in piston attenuators used as precision laboratory standards, and in the honeycomb vent panels that let air through an EMI-shielded enclosure while blocking microwave leakage. The same physics defines how close to cutoff a practical guide can run before guide wavelength dispersion and attenuation become unacceptable.

Governing Equations

Cutoff wavelength, rectangular TEmn/TMmn:
λc = 2 / √[ (m/a)2 + (n/b)2 ]

Dominant TE10 mode:
λc = 2a  →  fc = c / 2a

Circular waveguide, TE11 (dominant):
λc ≈ 1.706 × D  (D = bore diameter)

Guide wavelength vs. cutoff:
λg = λ / √[ 1 − (λ / λc)2 ]

Below-cutoff attenuation:
α = (2π / λc) × √[ 1 − (λc / λ)2 ]  Np/m

Where a, b = broad- and narrow-wall widths; m, n = mode indices; c ≈ 2.998 × 108 m/s; λ = free-space wavelength. Example: WR-90 TE10, a = 22.86 mm → λc = 45.72 mm, fc = 6.557 GHz.

Standard Waveguide Cutoff Values (TE10)

WaveguideBroad wall a (mm)Cutoff λc (mm)Cutoff fc (GHz)Recommended band (GHz)Band name
WR-34086.36172.71.7362.20 to 3.30S
WR-15940.3980.783.7114.90 to 7.05C
WR-9022.8645.726.5578.20 to 12.4X
WR-6215.8031.609.48812.4 to 18.0Ku
WR-287.11214.2221.0826.5 to 40.0Ka
WR-153.7597.51839.8850.0 to 75.0V
WR-102.5405.08059.0175.0 to 110W
Common Questions

Frequently Asked Questions

How do you calculate the cutoff wavelength of a rectangular waveguide?

Use λc = 2 / √[(m/a)2 + (n/b)2], where a and b are the broad- and narrow-wall dimensions and m, n are the mode indices. For the dominant TE10 mode this collapses to λc = 2a. A WR-90 guide has a = 22.86 mm, so λc = 45.72 mm, equivalent to a cutoff frequency of 6.557 GHz. Because λc depends only on geometry, the same guide cuts off at the same wavelength no matter what dielectric fills it.

Why does a signal below the cutoff frequency not propagate through a waveguide?

When the free-space wavelength exceeds λc, the propagation constant becomes purely imaginary and the mode is evanescent: the field decays as exp(−αz) instead of traveling. For TE10 well below cutoff the rolloff is about 27.3 dB per broad-wall width, so a short length of below-cutoff guide is an extremely high-rejection barrier. That principle drives WBCO attenuators and the honeycomb EMI vents used in shielded enclosures.

What is the relationship between cutoff wavelength and guide wavelength?

They are linked by λg = λ / √[1 − (λ/λc)2]. As the operating wavelength approaches λc, the radical approaches zero and λg grows without bound, which is why phase velocity rises and group velocity collapses near cutoff. Far above cutoff, λg approaches the free-space wavelength. Practical guides therefore run roughly 1.25 to 1.9 times the cutoff frequency to keep dispersion and loss in check.

Does filling a waveguide with dielectric change its cutoff wavelength?

No. The cutoff wavelength is purely a geometric property of the cross-section, so it stays the same regardless of the fill. What changes is the cutoff frequency: fc drops by a factor of √εr because the wave travels slower in the dielectric. Designers use this to shrink a guide's operating band downward without altering the metal dimensions, at the cost of higher loss tangent and some power-handling penalty.

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