Average Fade Duration
Understanding Average Fade Duration
In a multipath fading environment, the received signal envelope fluctuates rapidly as the mobile receiver moves through constructive and destructive interference patterns. When the envelope drops below a threshold (typically set at the receiver sensitivity or the FEC coding threshold), a burst of errors occurs until the signal recovers. The AFD tells the designer how long, on average, each of these error bursts lasts. Combined with the level crossing rate (how often the signal crosses the threshold), AFD completely characterizes the second-order temporal statistics of the fading process.
AFD is inversely proportional to the maximum Doppler frequency (fm = v/λ), which means faster-moving vehicles experience shorter but more frequent fades. At 1.9 GHz and 120 km/h, each fade at the -10 dB threshold lasts only about 0.37 ms. At walking speed (5 km/h), the same fade lasts approximately 8.9 ms. This speed dependence has critical implications: slow-moving users experience long burst errors that challenge interleaver design, while fast-moving users experience short fades that are easier to code through but complicate channel estimation.
AFD Formulas
τ̄ = (eρ2 - 1) / (ρ × fm × √(2π))
Where:
ρ = R / Rrms (threshold normalized to RMS level)
fm = v / λ (maximum Doppler frequency, Hz)
v = mobile velocity (m/s), λ = wavelength (m)
Level Crossing Rate (Rayleigh):
NR = √(2π) × fm × ρ × e-ρ2
Relationship:
P(r < R) = NR × τ̄ = 1 - e-ρ2
Burst Error Length:
Lburst = τ̄ × Rdata (bits)
AFD at 1.9 GHz by Speed and Threshold
| Speed | fm (Hz) | AFD at -10 dB | AFD at -20 dB | Burst Length at 1 Mbps (-10 dB) |
|---|---|---|---|---|
| 5 km/h (walk) | 8.8 | 8.9 ms | 1.0 ms | 8,900 bits |
| 30 km/h (urban) | 52.8 | 1.49 ms | 0.17 ms | 1,490 bits |
| 60 km/h (suburban) | 105.7 | 0.74 ms | 0.084 ms | 740 bits |
| 120 km/h (highway) | 211.4 | 0.37 ms | 0.042 ms | 370 bits |
Frequently Asked Questions
How is average fade duration calculated for a Rayleigh fading channel?
For Rayleigh fading, AFD equals (e^(rho^2) - 1) / (rho times f_m times sqrt(2*pi)), where rho is the threshold normalized to the RMS level and f_m is the maximum Doppler frequency (v/lambda). At 1.9 GHz with a vehicle at 60 km/h (f_m = 105.7 Hz) and a threshold 10 dB below the RMS level (rho = 0.316), the AFD is approximately 0.74 ms. At 1 Mbps, this corresponds to about 740 corrupted bits per fade event. Deeper thresholds produce shorter fades because the signal spends less time at extreme levels.
What is the relationship between AFD and level crossing rate?
AFD and level crossing rate (LCR) are complementary second-order statistics connected by the fade probability: P(r less than R) = AFD times N_R. For Rayleigh fading, N_R = sqrt(2*pi) * f_m * rho * exp(-rho^2). At deep fade levels (small rho), fades are infrequent but long. At shallow levels (rho near 1), fades are frequent but short. Together, AFD and LCR completely describe the temporal fading behavior needed for system design.
How does AFD affect interleaver design?
The interleaver depth must be 5 to 10 times the average burst error length (AFD times data rate) to spread burst errors across multiple codewords. For an AFD of 1 ms at 10 Mbps, the burst length is 10,000 bits, requiring 50,000 to 100,000 bits of interleaving. In LTE, turbo code interleavers (up to 6,144 bits) combine with channel interleaving across the 1 ms TTI and OFDM frequency diversity across 1,200 subcarriers. At mmWave frequencies, higher Doppler rates produce shorter fades, which actually relaxes the interleaver requirement.